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Revision as of 09:40, 9 September 2018
<script> window.onload=function() { // body... var prev=document.getElementById("prev"); var next=document.getElementById("next"); var list=document.getElementById("list"); var buttons=document.getElementById("buttons").getElementsByTagName("span"); var container=document.getElementById("container"); var index=1; var timer; var animated=false; function shownButton(){ for (var i = 0; i < buttons.length ; i++) { if( buttons[i].className == 'on'){ buttons[i].className = ; /* prev和next每click一次, 就会清除一次前一个class为on的span元素, 所以没有必要再去循环下面的span*/ break; } // 或者直接遍历清除 buttons[i].className=""; } buttons[index -1].className="on"; } function animate(offset){ var time = 300; var inteval = 10; var speed = offset/(time/inteval); animated=true; var newLeft=parseInt(list.style.left) +offset; function go(){ if ( (speed > 0 && parseInt(list.style.left) < newLeft) || (speed < 0 && parseInt(list.style.left) > newLeft)) { list.style.left = parseInt(list.style.left) + speed + 'px'; setTimeout(go, inteval); } else { animated=false; // list.style.left=newLeft+"px"; if (newLeft >-600) { list.style.left=-3000+"px"; }; if (newLeft <-3000) { list.style.left=-600+"px"; }; } } go(); }; prev.onclick=function(){ /*添加一个if判断index为1时,如果继续往前滚的话就让index返回第五个span 但是当快速点击arrow时会出现一种span点亮延迟的情况。可以尝试把判断index是否大于1或小于5的情况放进 判断是否animated的if语句中,先判断能不能点击,再点亮。 */ if (!animated) { if (index==1) { index=5; }else { index -=1; } shownButton(); animate(600); } }; next.onclick=function(){ if (!animated) { if (index==5) { index=1; }else { index +=1; } shownButton(); animate(-600); } }; for (var i = 0; i < buttons.length; i++) { buttons[i].onclick=function(){ //无关紧要 if (this.className=="on") { return; } var myIndex=parseInt(this.getAttribute("index")); var offset=-600*(myIndex-index); if (!animated) { animate(offset); } index=myIndex; shownButton(); } } function play(){ timer=setInterval(function(){ next.onclick(); },2000); } function stop(){ clearInterval(timer); } play(); container.onmouseover=stop; container.onmouseout=play; } </script>