Difference between revisions of "Team:NCKU Tainan/Kinetic Law"

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                                         <p class="pcontent">$${v = {v^{max}_f S/K_{m,1} - v^{max}_b P/K_{m,2} \over (1 + S/K_{m,1} + P/K_{m,1})}}$$</p>
 
                                         <p class="pcontent">$${v = {v^{max}_f S/K_{m,1} - v^{max}_b P/K_{m,2} \over (1 + S/K_{m,1} + P/K_{m,1})}}$$</p>
 
                                         <p class="pcontent">Where V<sub>f</sub> is the forward rate and the Vb is backwared rate while $${K_{m,1} = {K_{-1} + K_2 \over K_1}}$$ or represents as KS,  
 
                                         <p class="pcontent">Where V<sub>f</sub> is the forward rate and the Vb is backwared rate while $${K_{m,1} = {K_{-1} + K_2 \over K_1}}$$ or represents as KS,  
                                             and $${K_{m,2} = {K_{-1} + K_2 \over K_{-2}}}$$ or represent as KP.</p>
+
                                             and $${K_{m,2} = {K_{-1} + K_2 \over K_{-2}}}$$ or represent as K<sub>P</sub>.</p>
 
                                         <li id="ping_pong_bi_bi">Ping-Pong-Bi-Bi</li>
 
                                         <li id="ping_pong_bi_bi">Ping-Pong-Bi-Bi</li>
 
                                         <p class="pcontent">For Ping-Pong-Bi-Bi, it is a double displacement reactions.  
 
                                         <p class="pcontent">For Ping-Pong-Bi-Bi, it is a double displacement reactions.  

Revision as of 12:47, 14 October 2018

Kinetic law

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