Difference between revisions of "Team:TJU China/Model"
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<div style="margin-top:50px;">test</div> | <div style="margin-top:50px;">test</div> | ||
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| − | When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are | + | When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$ |
</div> | </div> | ||
Revision as of 16:03, 16 October 2018
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test
When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$