Difference between revisions of "Team:NCKU Tainan/Results"

Line 619: Line 619:
 
                                         $${=\ {0.0066704\over 12}}$$
 
                                         $${=\ {0.0066704\over 12}}$$
  
                                         $${=\ 0.5558\ {g\over L ∙hr}}$$
+
                                         $${=\ 0.5558\ {mg\over L ∙hr}}$$
  
 
                                         To find out how much carbon in biomass comes from the carbon in CO<sub>2</sub> captured by
 
                                         To find out how much carbon in biomass comes from the carbon in CO<sub>2</sub> captured by

Revision as of 13:25, 15 October 2018

Results

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