Difference between revisions of "Team:NCKU Tainan/Kinetic Law"

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                                         <p class="pcontent">$${{d[ES] \over dt} = k_1[E] \cdot [S] + k_{-2}[E] \cdot [P] - (k_{-1} + k_2)[ES]}$$</p>
 
                                         <p class="pcontent">$${{d[ES] \over dt} = k_1[E] \cdot [S] + k_{-2}[E] \cdot [P] - (k_{-1} + k_2)[ES]}$$</p>
 
                                         <p class="pcontent">$${{d[E] \over dt} = k_1[E] \cdot [S] - k_{-2}[E] \cdot [P] - (k_{-1} + k_2)[ES]}$$</p>
 
                                         <p class="pcontent">$${{d[E] \over dt} = k_1[E] \cdot [S] - k_{-2}[E] \cdot [P] - (k_{-1} + k_2)[ES]}$$</p>
                                         <p class="pcontent">$${v = {d[P] \over dt} = k_2[ES] - k_{-2}E \cdot [P] = v_f - v_b}$$</p>
+
                                         <p class="pcontent">$${v = {d[P] \over dt} = k_2[ES] - k_{-2}[E]\cdot [P] = v_f - v_b}$$</p>
 
                                         <p class="pcontent">After derivation $${v = {-ds \over dt} = {d[P] \over dt}}$$</p>
 
                                         <p class="pcontent">After derivation $${v = {-ds \over dt} = {d[P] \over dt}}$$</p>
 
                                         <p class="pcontent">Finally we use V<sub>fmax</sub> = k2⋅Etotal and V<sub>bmax</sub> = k<sub>−1</sub>⋅Etotal to get the common form for the reversible Michaelis Menten equation</p>
 
                                         <p class="pcontent">Finally we use V<sub>fmax</sub> = k2⋅Etotal and V<sub>bmax</sub> = k<sub>−1</sub>⋅Etotal to get the common form for the reversible Michaelis Menten equation</p>

Revision as of 19:49, 17 October 2018

Kinetic law

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