Difference between revisions of "Team:NCHU Taichung/test"
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When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are | When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are | ||
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$</p> | $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$</p> | ||
| + | <html> | ||
fuck | fuck | ||
fuck | fuck | ||
| + | </html> | ||
Revision as of 14:37, 13 October 2018
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When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
fuck fuck