Difference between revisions of "Team:NCHU Taichung/test"

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When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
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$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

Revision as of 14:29, 13 October 2018

<script type="text/x-mathjax-config"> MathJax.Hub.Config({

 tex2jax: {inlineMath: [['$','$'], ['\\(','\\)']]}

}); </script> When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$