Line 10: | Line 10: | ||
</head> | </head> | ||
<body> | <body> | ||
+ | <p> | ||
When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are | When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are | ||
− | $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ | + | $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$</p> |
</body> | </body> | ||
</html> | </html> |
Revision as of 14:36, 13 October 2018